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Therefore, he'll work if <math>s_{i}z-1>0 \iff s_{i}z>1 \iff s_{i}>\frac{1}{z}</math>.
<b>Note</b> that not everyone can have <math>s_{i}>\frac{1}{z}</math> because <math>\sum s_i=\frac{N}{z}>1</math>.
(a) <i>My answer, assuming that all shares must be equal</i>.
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