Difference between revisions of "VC Bargaining"

From edegan.com
Jump to navigation Jump to search
imported>Ed
imported>Ed
Line 37: Line 37:
 
Assume a fixed number of rounds: <math>t={1,2}\,</math>
 
Assume a fixed number of rounds: <math>t={1,2}\,</math>
 
Assume a fixed total investment: <math>\sum_t x_t = 1\,</math>
 
Assume a fixed total investment: <math>\sum_t x_t = 1\,</math>
Assume a functional form for <math>f(x_t): f(x_t) = ln (x_t)\,</math>
+
Assume a functional form for <math>f(x_t): f(x_t) = x_t^\frac{1}{2}\,</math>
  
 
Again <math> V(0)=0 \,</math>.
 
Again <math> V(0)=0 \,</math>.
  
:<math> \therefore V_2 = ln(x_1) + ln(x_2)\,</math>
+
:<math> \therefore V_2 = x_1^\frac{1}{2} + x_2^\frac{1}{2}\,</math>

Revision as of 20:37, 25 May 2011

This page (and the discussion page) is for Ed and Ron to share their thoughts on VC Bargaining. Access is restricted to those with "Trusted" access.

A Basic Model

The players

The players are an Entrepreneur and a VC, both are risk neutral.

The Value Function

[math]V_t=V_{t-1} + f(x_t) - k \,[/math]

with

[math]V_0=0, f(0)=0, f'\gt 0, f''\lt 0, k\gt 0 \,[/math]

Having [math]k\gt 0\,[/math] forces a finite number of rounds as the optimal solution providing there is a stopping constraint on [math]V_t\,[/math] (so players don't invest forever).

One possible stopping constraint is:

[math]V_t \ge \overline{V}\,[/math]

with

[math]\overline{V} \sim F(V)\,[/math]

where the distribution is known to both parties.

Bargaining

In each period there is Rubenstein finite bargaining, with potentially different patience, and one player designated as last. This will give a single period equilibrium outcome with the parties having different bargaining strength.

Simple First Steps

Address the question: How does the optimal policy compare to the current way of calculating shares and values?

Assume a fixed number of rounds: [math]t={1,2}\,[/math] Assume a fixed total investment: [math]\sum_t x_t = 1\,[/math] Assume a functional form for [math]f(x_t): f(x_t) = x_t^\frac{1}{2}\,[/math]

Again [math] V(0)=0 \,[/math].

[math] \therefore V_2 = x_1^\frac{1}{2} + x_2^\frac{1}{2}\,[/math]